David estimated he had about 20 fish in his pond. A year later, there were about 1.5 times as many fish. The year after that, the number of fish increased by a factor of 1.5 again. The number of fish is modeled by f(x)=20(1.5)^x.Create a question you could ask that could be answered only by graphing or using a logarithm.

Answer:After how many years is the fish population 60?x=2.71 yearsStep-by-step explanation:The fish population increases by a factor of 1.5 each year. We have the equation that represents this situation[tex]f (x) = 20 (1.5) ^ x[/tex]Where x represents the number of years elapsed f(x) represents the amount of fish.Given this situation, the following question could be posedAfter how many years is the fish population 60?So we do [tex]f (x) = 60[/tex] and solve for the variable x[tex]60 = 20 (1.5) ^ x\\\\\frac{60}{20} = (1.5)^x\\\\3 = (1.5)^x\\\\log_{1.5}(3) = log_{1.5}(1.5)^x\\\\log_{1.5}(3) = x\\\\x =log_{1.5}(3)\\\\x=2.71\ years[/tex]Observe the solution in the attached graph