MATH SOLVE

4 months ago

Q:
# 3c-2(c+10)=7c-5(c+2)

Accepted Solution

A:

Answer: C= -10Step-by-step explanation: First step: simplify both sides of the equation 3cβ2(c+10)=7cβ5(c+2)3c+(β2)(c)+(β2)(10)=7c+(β5)(c)+(β5)(2) (Distribute)3c+β2c+β20=7c+β5c+β10(3c+β2c)+(β20)=(7c+β5c)+(β10) (Combine Like Terms)c + -20 = 2c - 10c - 20 = 2c - 10Step 2: Subtract 2c from both sidesc - 20 - 2c = 2c -10 - 2cβcβ20=β10Step 3: Add 20 to both sidesβcβ20+20=β10+20βc=10Step 4: Divide both sides by -1-c/-1 = 10/-1C=-10 Β Β