3c-2(c+10)=7c-5(c+2)

Answer: C= -10Step-by-step explanation: First step: simplify both sides of the equation 3c−2(c+10)=7c−5(c+2)3c+(−2)(c)+(−2)(10)=7c+(−5)(c)+(−5)(2) (Distribute)3c+−2c+−20=7c+−5c+−10(3c+−2c)+(−20)=(7c+−5c)+(−10) (Combine Like Terms)c + -20 = 2c - 10c - 20 = 2c - 10Step 2: Subtract 2c from both sidesc - 20 - 2c = 2c -10 - 2c−c−20=−10Step 3: Add 20 to both sides−c−20+20=−10+20−c=10Step 4: Divide both sides by -1-c/-1 = 10/-1C=-10